Adam has 135 red beads.
He has 3 times as many red beads than blue beads.
After he gives away an equal number of red and blue beads,
the number of red beads is 6 times that of the blue beads.
- How many red beads are there in the end?
- How many blue beads are there in the end?
- How many beads are there in the end?
- How many beads does Adam give away?
|
Red beads |
Blue beads |
Difference |
Before |
3 x 5 = 15 u |
1 x 5 = 5 u |
2 x 5 = 10 u |
Change |
- ? |
- ? |
|
After |
6 x 2 = 12 u |
1 x 2 = 2 u |
5 x 2 = 10 u |
(a)
The difference in the number between the red and blue beads at first and in the end remains unchanged.
LCM of 2 and 5 is 10.
15 u = 135
1 u = 135 ÷ 15 = 9
Number of red beads in the end
= 12 u
= 12 x 9
= 108
(b)
Number of blue beads in the end
= 2 u
= 2 x 9
= 18
(c)
Total number of beads in the end
= 108 + 18
= 126
(d)
Total number of beads that Adam gives away
= (15 u - 12 u) x 2
= 3 u x 2
= 6 u
= 6 x 9
= 54
Answer(s): (a) 108; (b) 18; (c) 126; (d) 54