Adam has 12 red beads.
He has 2 times as many red beads than blue beads.
After he gives away an equal number of red and blue beads,
the number of red beads is 3 times that of the blue beads.
- How many red beads are there in the end?
- How many blue beads are there in the end?
- How many beads are there in the end?
- How many beads does Adam give away?
|
Red beads |
Blue beads |
Difference |
Before |
2 x 2 = 4 u |
1 x 2 = 2 u |
1 x 2 = 2 u |
Change |
- ? |
- ? |
|
After |
3 x 1 = 3 u |
1 x 1 = 1 u |
2 x 1 = 2 u |
(a)
The difference in the number between the red and blue beads at first and in the end remains unchanged.
LCM of 1 and 2 is 2.
4 u = 12
1 u = 12 ÷ 4 = 3
Number of red beads in the end
= 3 u
= 3 x 3
= 9
(b)
Number of blue beads in the end
= 1 u
= 1 x 3
= 3
(c)
Total number of beads in the end
= 9 + 3
= 12
(d)
Total number of beads that Adam gives away
= (4 u - 3 u) x 2
= 1 u x 2
= 2 u
= 2 x 3
= 6
Answer(s): (a) 9; (b) 3; (c) 12; (d) 6