Adam has 160 blue beads.
He has 2 times as many blue beads than red beads.
After he gives away an equal number of blue and red beads,
the number of blue beads is 5 times that of the red beads.
- How many blue beads are there in the end?
- How many red beads are there in the end?
- How many beads are there in the end?
- How many beads does Adam give away?
|
Blue beads |
Red beads |
Difference |
Before |
2 x 4 = 8 u |
1 x 4 = 4 u |
1 x 4 = 4 u |
Change |
- ? |
- ? |
|
After |
5 x 1 = 5 u |
1 x 1 = 1 u |
4 x 1 = 4 u |
(a)
The difference in the number between the blue and red beads at first and in the end remains unchanged.
LCM of 1 and 4 is 4.
8 u = 160
1 u = 160 ÷ 8 = 20
Number of blue beads in the end
= 5 u
= 5 x 20
= 100
(b)
Number of red beads in the end
= 1 u
= 1 x 20
= 20
(c)
Total number of beads in the end
= 100 + 20
= 120
(d)
Total number of beads that Adam gives away
= (8 u - 5 u) x 2
= 3 u x 2
= 6 u
= 6 x 20
= 120
Answer(s): (a) 100; (b) 20; (c) 120; (d) 120