Adam has 28 blue beads.
He has 2 times as many blue beads than red beads.
After he gives away an equal number of blue and red beads,
the number of blue beads is 3 times that of the red beads.
- How many blue beads are there in the end?
- How many red beads are there in the end?
- How many beads are there in the end?
- How many beads does Adam give away?
|
Blue beads |
Red beads |
Difference |
Before |
2 x 2 = 4 u |
1 x 2 = 2 u |
1 x 2 = 2 u |
Change |
- ? |
- ? |
|
After |
3 x 1 = 3 u |
1 x 1 = 1 u |
2 x 1 = 2 u |
(a)
The difference in the number between the blue and red beads at first and in the end remains unchanged.
LCM of 1 and 2 is 2.
4 u = 28
1 u = 28 ÷ 4 = 7
Number of blue beads in the end
= 3 u
= 3 x 7
= 21
(b)
Number of red beads in the end
= 1 u
= 1 x 7
= 7
(c)
Total number of beads in the end
= 21 + 7
= 28
(d)
Total number of beads that Adam gives away
= (4 u - 3 u) x 2
= 1 u x 2
= 2 u
= 2 x 7
= 14
Answer(s): (a) 21; (b) 7; (c) 28; (d) 14