Adam has 54 red beads.
He has 3 times as many red beads than blue beads.
After he gives away an equal number of red and blue beads,
the number of red beads is 5 times that of the blue beads.
- How many red beads are there in the end?
- How many blue beads are there in the end?
- How many beads are there in the end?
- How many beads does Adam give away?
|
Red beads |
Blue beads |
Difference |
Before |
3 x 2 = 6 u |
1 x 2 = 2 u |
2 x 2 = 4 u |
Change |
- ? |
- ? |
|
After |
5 x 1 = 5 u |
1 x 1 = 1 u |
4 x 1 = 4 u |
(a)
The difference in the number between the red and blue beads at first and in the end remains unchanged.
LCM of 2 and 4 is 4.
6 u = 54
1 u = 54 ÷ 6 = 9
Number of red beads in the end
= 5 u
= 5 x 9
= 45
(b)
Number of blue beads in the end
= 1 u
= 1 x 9
= 9
(c)
Total number of beads in the end
= 45 + 9
= 54
(d)
Total number of beads that Adam gives away
= (6 u - 5 u) x 2
= 1 u x 2
= 2 u
= 2 x 9
= 18
Answer(s): (a) 45; (b) 9; (c) 54; (d) 18