Adam has 20 blue beads.
He has 2 times as many blue beads than red beads.
After he gives away an equal number of blue and red beads,
the number of blue beads is 6 times that of the red beads.
- How many blue beads are there in the end?
- How many red beads are there in the end?
- How many beads are there in the end?
- How many beads does Adam give away?
|
Blue beads |
Red beads |
Difference |
Before |
2 x 5 = 10 u |
1 x 5 = 5 u |
1 x 5 = 5 u |
Change |
- ? |
- ? |
|
After |
6 x 1 = 6 u |
1 x 1 = 1 u |
5 x 1 = 5 u |
(a)
The difference in the number between the blue and red beads at first and in the end remains unchanged.
LCM of 1 and 5 is 5.
10 u = 20
1 u = 20 ÷ 10 = 2
Number of blue beads in the end
= 6 u
= 6 x 2
= 12
(b)
Number of red beads in the end
= 1 u
= 1 x 2
= 2
(c)
Total number of beads in the end
= 12 + 2
= 14
(d)
Total number of beads that Adam gives away
= (10 u - 6 u) x 2
= 4 u x 2
= 8 u
= 8 x 2
= 16
Answer(s): (a) 12; (b) 2; (c) 14; (d) 16