Ahmad and Bradley have the same amount of money.
Ahmad receives $90 and Bradley receives $10.
In the end, Ahmad has 5 times as much money as Bradley.
- How much does each of them have at first?
- How much does Bradley have less than Ahmad in the end?
|
Ahmad |
Bradley |
Before |
5 u - 90 |
1 u - 10 |
Change |
+ 90 |
+ 10 |
After |
5 u |
1 u |
(a)
At first
Amount that Ahmad has = Amount that Bradley has
5 u - 90 = 1 u - 10
5 u - 1 u = 90 - 10
4 u = 80
1 u = 80 ÷ 4 = 20
Amount that each of them has at first
= 1 u - 10
= 20 - 10
= $10
(b)
Amount that Bradley has less than Ahmad in the end
= 5 u - 1 u
= 4 u
= 4 x 20
= $80
Answer(s): (a) $10; (b) $80