Albert and Baxter have the same amount of money.
Albert receives $90 and Baxter receives $10.
In the end, Albert has 6 times as much money as Baxter.
- How much does each of them have at first?
- How much does Baxter have less than Albert in the end?
|
Albert |
Baxter |
Before |
6 u - 90 |
1 u - 10 |
Change |
+ 90 |
+ 10 |
After |
6 u |
1 u |
(a)
At first
Amount that Albert has = Amount that Baxter has
6 u - 90 = 1 u - 10
6 u - 1 u = 90 - 10
5 u = 80
1 u = 80 ÷ 5 = 16
Amount that each of them has at first
= 1 u - 10
= 16 - 10
= $6
(b)
Amount that Baxter has less than Albert in the end
= 6 u - 1 u
= 5 u
= 5 x 16
= $80
Answer(s): (a) $6; (b) $80