Abraham and Bentley have the same amount of money.
Abraham receives $90 and Bentley receives $10.
In the end, Abraham has 6 times as much money as Bentley.
- How much does each of them have at first?
- How much does Bentley have less than Abraham in the end?
|
Abraham |
Bentley |
Before |
6 u - 90 |
1 u - 10 |
Change |
+ 90 |
+ 10 |
After |
6 u |
1 u |
(a)
At first
Amount that Abraham has = Amount that Bentley has
6 u - 90 = 1 u - 10
6 u - 1 u = 90 - 10
5 u = 80
1 u = 80 ÷ 5 = 16
Amount that each of them has at first
= 1 u - 10
= 16 - 10
= $6
(b)
Amount that Bentley has less than Abraham in the end
= 6 u - 1 u
= 5 u
= 5 x 16
= $80
Answer(s): (a) $6; (b) $80