Ahmad and Brody have the same amount of money.
Ahmad receives $90 and Brody receives $20.
In the end, Ahmad has 3 times as much money as Brody.
- How much does each of them have at first?
- How much does Brody have less than Ahmad in the end?
|
Ahmad |
Brody |
Before |
3 u - 90 |
1 u - 20 |
Change |
+ 90 |
+ 20 |
After |
3 u |
1 u |
(a)
At first
Amount that Ahmad has = Amount that Brody has
3 u - 90 = 1 u - 20
3 u - 1 u = 90 - 20
2 u = 70
1 u = 70 ÷ 2 = 35
Amount that each of them has at first
= 1 u - 20
= 35 - 20
= $15
(b)
Amount that Brody has less than Ahmad in the end
= 3 u - 1 u
= 2 u
= 2 x 35
= $70
Answer(s): (a) $15; (b) $70