Aaron and Brendon have the same amount of money.
Aaron receives $80 and Brendon receives $10.
In the end, Aaron has 6 times as much money as Brendon.
- How much does each of them have at first?
- How much does Brendon have less than Aaron in the end?
|
Aaron |
Brendon |
Before |
6 u - 80 |
1 u - 10 |
Change |
+ 80 |
+ 10 |
After |
6 u |
1 u |
(a)
At first
Amount that Aaron has = Amount that Brendon has
6 u - 80 = 1 u - 10
6 u - 1 u = 80 - 10
5 u = 70
1 u = 70 ÷ 5 = 14
Amount that each of them has at first
= 1 u - 10
= 14 - 10
= $4
(b)
Amount that Brendon has less than Aaron in the end
= 6 u - 1 u
= 5 u
= 5 x 14
= $70
Answer(s): (a) $4; (b) $70