Adriel and Baxter have the same amount of money.
Adriel receives $80 and Baxter receives $20.
In the end, Adriel has 3 times as much money as Baxter.
- How much does each of them have at first?
- How much does Baxter have less than Adriel in the end?
|
Adriel |
Baxter |
Before |
3 u - 80 |
1 u - 20 |
Change |
+ 80 |
+ 20 |
After |
3 u |
1 u |
(a)
At first
Amount that Adriel has = Amount that Baxter has
3 u - 80 = 1 u - 20
3 u - 1 u = 80 - 20
2 u = 60
1 u = 60 ÷ 2 = 30
Amount that each of them has at first
= 1 u - 20
= 30 - 20
= $10
(b)
Amount that Baxter has less than Adriel in the end
= 3 u - 1 u
= 2 u
= 2 x 30
= $60
Answer(s): (a) $10; (b) $60