Adriel and Boaz have the same amount of money.
Adriel receives $70 and Boaz receives $20.
In the end, Adriel has 3 times as much money as Boaz.
- How much does each of them have at first?
- How much does Boaz have less than Adriel in the end?
|
Adriel |
Boaz |
Before |
3 u - 70 |
1 u - 20 |
Change |
+ 70 |
+ 20 |
After |
3 u |
1 u |
(a)
At first
Amount that Adriel has = Amount that Boaz has
3 u - 70 = 1 u - 20
3 u - 1 u = 70 - 20
2 u = 50
1 u = 50 ÷ 2 = 25
Amount that each of them has at first
= 1 u - 20
= 25 - 20
= $5
(b)
Amount that Boaz has less than Adriel in the end
= 3 u - 1 u
= 2 u
= 2 x 25
= $50
Answer(s): (a) $5; (b) $50