A coin bank contains some twenty-cent and fifty-cent coins in the ratio of 5 : 4.
When 10 fifty-cent coins are taken out and
exchanged with some twenty-cent coins of the same value,
the ratio became 10 : 7.
Find the sum of money in the coin box in dollars.
|
Make p the same. (1) x 7 = (3) |
(1) 20-cent |
(2) 50-cent |
Make p the same. (2) x 10 = (4) |
Before |
35 u |
5 u |
4 u |
40 u |
Change |
+ 175 |
+ 25 |
- 10 |
- 100 |
After |
70 p |
10 p |
7 p |
70 p |
Value of 10 fifty-cent coins
= 10 x 50
= 500¢
Number of twenty-cent coins to exchange for
= 500 ÷ 20
= 25
5 u + 25 = 10 p --- (1)
4 u - 10 = 7 p --- (2)
Make p the same.
(1)
x 7 35 u + 175 = 70 p --- (3)
(2)
x 10 40 u - 100 = 70 p --- (4)
(4) = (3)
40 u - 100 = 35 u + 175
40 u - 35 u = 175 + 100
5 u = 275
1 u = 275 ÷ 5 = 55
Value of twenty-cent coins
= 5 u x 20
= 5 x 55 x 20
= 5500¢
Value of fifty-cent coins
= 4 u x 50
= 4 x 55 x 50
= 11000¢
Total value of coins
= 5500 + 11000
= 16500¢
100¢ = $1
Sum of money in the coin box
= 16500¢
= $165
Answer(s): $165