A coin bank contains some ten-cent and twenty-cent coins in the ratio of 4 : 5.
When 14 twenty-cent coins are taken out and
exchanged with some ten-cent coins of the same value,
the ratio became 6 : 7.
Find the sum of money in the coin box in dollars.
|
Make p the same. (1) x 7 = (3) |
(1) 10-cent |
(2) 20-cent |
Make p the same. (2) x 6 = (4) |
Before |
28 u |
4 u |
5 u |
30 u |
Change |
+ 196 |
+ 28 |
- 14 |
- 84 |
After |
42 p |
6 p |
7 p |
42 p |
Value of 14 twenty-cent coins
= 14 x 20
= 280¢
Number of ten-cent coins to exchange for
= 280 ÷ 10
= 28
4 u + 28 = 6 p --- (1)
5 u - 14 = 7 p --- (2)
Make p the same.
(1)
x 7 28 u + 196 = 42 p --- (3)
(2)
x 6 30 u - 84 = 42 p --- (4)
(4) = (3)
30 u - 84 = 28 u + 196
30 u - 28 u = 196 + 84
2 u = 280
1 u = 280 ÷ 2 = 140
Value of ten-cent coins
= 4 u x 10
= 4 x 140 x 10
= 5600¢
Value of twenty-cent coins
= 5 u x 20
= 5 x 140 x 20
= 14000¢
Total value of coins
= 5600 + 14000
= 19600¢
100¢ = $1
Sum of money in the coin box
= 19600¢
= $196
Answer(s): $196