A coin bank contains some five-cent and twenty-cent coins in the ratio of 4 : 5.
When 5 twenty-cent coins are taken out and
exchanged with some five-cent coins of the same value,
the ratio became 7 : 8.
Find the sum of money in the coin box in dollars.
|
Make p the same. (1) x 8 = (3) |
(1) 5-cent |
(2) 20-cent |
Make p the same. (2) x 7 = (4) |
Before |
32 u |
4 u |
5 u |
35 u |
Change |
+ 160 |
+ 20 |
- 5 |
- 35 |
After |
56 p |
7 p |
8 p |
56 p |
Value of 5 twenty-cent coins
= 5 x 20
= 100¢
Number of five-cent coins to exchange for
= 100 ÷ 5
= 20
4 u + 20 = 7 p --- (1)
5 u - 5 = 8 p --- (2)
Make p the same.
(1)
x 8 32 u + 160 = 56 p --- (3)
(2)
x 7 35 u - 35 = 56 p --- (4)
(4) = (3)
35 u - 35 = 32 u + 160
35 u - 32 u = 160 + 35
3 u = 195
1 u = 195 ÷ 3 = 65
Value of five-cent coins
= 4 u x 5
= 4 x 65 x 5
= 1300¢
Value of twenty-cent coins
= 5 u x 20
= 5 x 65 x 20
= 6500¢
Total value of coins
= 1300 + 6500
= 7800¢
100¢ = $1
Sum of money in the coin box
= 7800¢
= $78
Answer(s): $78