Some passengers board a school bus.
At Bus Stop A,
25 of them alight
and 8 passengers board.
At Bus Stop B,
710 of the passengers alight
and 4 board.
If there are 10 passengers on the bus now,
how many passengers are on the bus at first?
|
Number of passengers |
Before |
5 u |
|
Change 1 At Bus Stop A |
- 2 u + 8 |
|
After 1 |
3 u + 8 |
10 p |
Change 2 At Bus Stop B |
|
- 7 p + 4 |
After 2 |
|
10 |
Working backwards.
Number of passengers in the end = 10
10 p - 7 p = 10 - 4
3 p = 6
1 p = 6 ÷ 3 = 2
10 p = 10 x 2
10 p = 20
3 u + 8 = 10 p
3 u + 8 = 20
3 u = 20 - 8
3 u = 12
1 u = 12 ÷ 3 = 4
Total number of passengers at first
= 5 u
= 5 x 4
= 20
Answer(s): 20