Some passengers board a school bus.
At Bus Stop A,
58 of them alight
and 5 passengers board.
At Bus Stop B,
35 of the passengers alight
and 3 board.
If there are 11 passengers on the bus now,
how many passengers are on the bus at first?
|
Number of passengers |
Before |
8 u |
|
Change 1 At Bus Stop A |
- 5 u + 5 |
|
After 1 |
3 u + 5 |
5 p |
Change 2 At Bus Stop B |
|
- 3 p + 3 |
After 2 |
|
11 |
Working backwards.
Number of passengers in the end = 11
5 p - 3 p = 11 - 3
2 p = 8
1 p = 8 ÷ 2 = 4
5 p = 5 x 4
5 p = 20
3 u + 5 = 5 p
3 u + 5 = 20
3 u = 20 - 5
3 u = 15
1 u = 15 ÷ 3 = 5
Total number of passengers at first
= 8 u
= 8 x 5
= 40
Answer(s): 40