Adam has 500 stickers.
⁹₁₀ of the stickers are sold in the morning.
⁴₅ of the remaining stickers are sold in the afternoon.
How many more stickers are sold in the afternoon than what are left?
Fraction of stickers left in the morning
= 1 - ⁹₁₀

= ¹₁₀

¹₁₀ of total stickers = ⁵₅ of remaining stickers

Make the numerators the same.
LCM of 1 and 5 is 5.

^{1 x 5} _{10 x 5} of total stickers = ^{5 x 1}_{5 x 1} of remaining stickers
⁵₅₀ of total stickers = ⁵₅ of remaining stickers

Total number of stickers at first = 50 u
Total number of stickers after selling some in the morning = 5 u

Number of stickers sold in the morning = 50 u - 5 u = 45 u
Number of stickers sold in the afternoon = 4 u
Number of stickers left = 5 u - 4 u = 1 u

50 u = 500

1 u = 500 ÷ 50 = 10

Number of more stickers sold in the afternoon than what is left
= 4 u - 1 u
= 3 u
= 3 x 10
= 30

Answer(s): 30