Adam has 360 stickers.
¹¹₁₂ of the stickers are sold in the morning.
⁹₁₀ of the remaining stickers are sold in the afternoon.
How many more stickers are sold in the afternoon than what are left?
Fraction of stickers left in the morning
= 1 - ¹¹₁₂

= ¹₁₂

¹₁₂ of total stickers = ¹⁰₁₀ of remaining stickers

Make the numerators the same.
LCM of 1 and 10 is 10.

^{1 x 10} _{12 x 10} of total stickers = ^{10 x 1}_{10 x 1} of remaining stickers
¹⁰₁₂₀ of total stickers = ¹⁰₁₀ of remaining stickers

Total number of stickers at first = 120 u
Total number of stickers after selling some in the morning = 10 u

Number of stickers sold in the morning = 120 u - 10 u = 110 u
Number of stickers sold in the afternoon = 9 u
Number of stickers left = 10 u - 9 u = 1 u

120 u = 360

1 u = 360 ÷ 120 = 3

Number of more stickers sold in the afternoon than what is left
= 9 u - 1 u
= 8 u
= 8 x 3
= 24

Answer(s): 24