Adam has 420 stickers.
²₇ of the stickers are sold in the morning.
⁵₆ of the remaining stickers are sold in the afternoon.
How many more stickers are sold in the afternoon than what are left?
Fraction of stickers left in the morning
= 1 - ²₇

= ⁵₇

⁵₇ of total stickers = ⁶₆ of remaining stickers

Make the numerators the same.
LCM of 5 and 6 is 30.

^{5 x 6} _{7 x 6} of total stickers = ^{6 x 5}_{6 x 5} of remaining stickers
³⁰₄₂ of total stickers = ³⁰₃₀ of remaining stickers

Total number of stickers at first = 42 u
Total number of stickers after selling some in the morning = 30 u

Number of stickers sold in the morning = 42 u - 30 u = 12 u
Number of stickers sold in the afternoon = 25 u
Number of stickers left = 30 u - 25 u = 5 u

42 u = 420

1 u = 420 ÷ 42 = 10

Number of more stickers sold in the afternoon than what is left
= 25 u - 5 u
= 20 u
= 20 x 10
= 200

Answer(s): 200