Adam has 440 stickers.
²₁₁ of the stickers are sold in the morning.
³₅ of the remaining stickers are sold in the afternoon.
How many more stickers are sold in the afternoon than what are left?
Fraction of stickers left in the morning
= 1 - ²₁₁

= ⁹₁₁

⁹₁₁ of total stickers = ⁵₅ of remaining stickers

Make the numerators the same.
LCM of 9 and 5 is 45.

^{9 x 5} _{11 x 5} of total stickers = ^{5 x 9}_{5 x 9} of remaining stickers
⁴⁵₅₅ of total stickers = ⁴⁵₄₅ of remaining stickers

Total number of stickers at first = 55 u
Total number of stickers after selling some in the morning = 45 u

Number of stickers sold in the morning = 55 u - 45 u = 10 u
Number of stickers sold in the afternoon = 27 u
Number of stickers left = 45 u - 27 u = 18 u

55 u = 440

1 u = 440 ÷ 55 = 8

Number of more stickers sold in the afternoon than what is left
= 27 u - 18 u
= 9 u
= 9 x 8
= 72

Answer(s): 72