Adam has some stickers.
²₅ of the stickers are sold in the morning.
¹₃ of the remainder are sold in the afternoon.
There are 30 more stickers sold in the morning than in the afternoon.

1. How many stickers does he have at first?
2. How many stickers does he have in the end?

(a)
Fraction of stickers left after selling in the morning
= 1 - ²₅
= ³₅

Make the numerators the same.
LCM of 3 and 3 is 3.

35 of the total stickers = 33 of the remaining stickers
3x15x1 of the total stickers = 33 of the remaining stickers
35 of the total stickers = 33 of the remaining stickers

Total number of stickers at first = 5 u
Total number of stickers after selling some in the morning = 3 u

Number of stickers sold in the morning = 5 u - 3 u = 2 u
Number of stickers sold in the afternoon = ¹₃ x 3 = 1 u
Number of stickers left = 3 u - 1 u = 2 u

Number of stickers sold more in the morning than the afternoon
= 2 u - 1 u
= 1 u

1 u = 30

1 u = 30 ÷ 1 = 30

Number of stickers Adam has at first
= 5 u
= 5 x 30
= 150

(b)
Number of stickers that Adam has in the end
= 2 u
= 2 x 30
= 60

Answer(s): (a) 150; (b) 60