Adam has some stickers.
12 of the stickers are sold in the morning.
611 of the remainder are sold in the afternoon.
There are 20 more stickers sold in the morning than in the afternoon.
- How many stickers does he have at first?
- How many stickers does he have in the end?
(a)
Fraction of stickers left after selling in the morning
= 1 -
12=
12 Make the numerators the same.
LCM of 1 and 11 is 11.
12 of the total stickers =
1111 of the remaining stickers
1x112x11 of the total stickers =
1111 of the remaining stickers
1122 of the total stickers =
1111 of the remaining stickers
Total number of stickers at first = 22 u
Total number of stickers after selling some in the morning = 11 u
Number of stickers sold in the morning = 22 u - 11 u = 11 u
Number of stickers sold in the afternoon =
611 x 11 = 6 u
Number of stickers left = 11 u - 6 u = 5 u
Number of stickers sold more in the morning than the afternoon
= 11 u - 6 u
= 5 u
5 u = 20
1 u = 20 ÷ 5 = 4
Number of stickers Adam has at first
= 22 u
= 22 x 4
= 88
(b)
Number of stickers that Adam has in the end
= 5 u
= 5 x 4
= 20
Answer(s): (a) 88; (b) 20