Bryan, Adam and Charlie have $1290.
After Bryan spends
35 of his money,
Adam spends
110 of his money and
Charlie spends
17 of his money,
they have equal amount of money left.
Find the total amount that the 3 children spend.
|
Bryan |
Adam |
Charlie |
Before |
5 x 9 = 45 u |
10 x 2 = 20 u |
7 x 3 = 21 u |
Change |
- 3 x 9 = - 27 u |
- 1 x 2 = - 2 u |
- 1 x 3 = - 3 u |
After |
2 x 9 = 18 u |
9 x 2 = 18 u |
6 x 3 = 18 u |
The lowest common multiple of 2, 9 and 6 is 18.
Fraction of the amount left after Bryan spends his money
= 1 -
35 =
25 Fraction of the amount left after Adam spends his money
= 1 -
110 =
910 Fraction of the amount left after Charlie spends his money
= 1 -
17 =
67 Make the numerators the same.
2 x 95 x 9 of Bryan's amount =
9 x 210 x 2 of Adam's amount =
6 x 37 x 3 of Charlie's amount
1845 of Bryan's amount =
1820 of Adam's amount =
1821 of Charlie's amount
Total amount that they have at first
= 45 u + 20 u + 21 u
= 86 u
86 u = 1290
1 u = 1290 ÷ 86 = 15
Amount that Bryan spends
= 45 u - 18 u
= 27 u
Amount that Adam spends
= 20 u - 18 u
= 2 u
Amount that Charlie spends
= 21 u - 18 u
= 3 u
Amount that they spend
= 27 u + 2 u + 3 u
= 32 u
= 32 x 15
= $480
Answer(s): $480