Bryan, Adam and Charlie have $644.
After Bryan spends
45 of his money,
Adam spends
13 of his money and
Charlie spends
17 of his money,
they have equal amount of money left.
Find the total amount that the 3 children spend.
| |
Bryan |
Adam |
Charlie |
| Before |
5 x 6 =
30 u |
3 x 3 =
9 u |
7 x 1 =
7 u |
| Change |
- 4 x 6 =
- 24 u |
- 1 x 3 =
- 3 u |
- 1 x 1 =
- 1 u |
| After |
1 x 6 =
6 u |
2 x 3 =
6 u |
6 x 1 =
6 u |
The lowest common multiple of 1, 2 and 6 is 6.
Fraction of the amount left after Bryan spends his money
= 1 -
45 =
15 Fraction of the amount left after Adam spends his money
= 1 -
13 =
23 Fraction of the amount left after Charlie spends his money
= 1 -
17 =
67 Make the numerators the same.
1 x 65 x 6 of Bryan's amount =
2 x 33 x 3 of Adam's amount =
6 x 17 x 1 of Charlie's amount
630 of Bryan's amount =
69 of Adam's amount =
67 of Charlie's amount
Total amount that they have at first
= 30 u + 9 u + 7 u
= 46 u
46 u = 644
1 u = 644 ÷ 46 = 14
Amount that Bryan spends
= 30 u - 6 u
= 24 u
Amount that Adam spends
= 9 u - 6 u
= 3 u
Amount that Charlie spends
= 7 u - 6 u
= 1 u
Amount that they spend
= 24 u + 3 u + 1 u
= 28 u
= 28 x 14
= $392
Answer(s): $392
