Adam, Bryan and Charlie have $590.
After Adam spends ³₅ of his money,
Bryan spends ¹₂ of his money and
Charlie spends ²₇ of his money,
they have equal amount of money left.
Find the total amount that the 3 children spend.

	Adam	Bryan	Charlie
Before	5 x 5 = 25 u	2 x 10 = 20 u	7 x 2 = 14 u
Change	- 3 x 5 = - 15 u	- 1 x 10 = - 10 u	- 2 x 2 = - 4 u
After	2 x 5 =  10 u	1 x 10 = 10 u	5 x 2 = 10 u

The lowest common multiple of 2, 1 and 5 is 10.

Fraction of the amount left after Adam spends his money
= 1 - ³₅
= ²₅

Fraction of the amount left after Bryan spends his money
= 1 - ¹₂
= ¹₂

Fraction of the amount left after Charlie spends his money
= 1 - ²₇
= ⁵₇

Make the numerators the same.
2 x 55 x 5 of Adam's amount = 1 x 102 x 10 of Bryan's amount = 5 x 27 x 2 of Charlie's amount
1025 of Adam's amount = 1020 of Bryan's amount = 1014 of Charlie's amount

Total amount that they have at first
= 25 u + 20 u + 14 u
= 59 u

59 u = 590

1 u = 590 ÷ 59 = 10

Amount that Adam spends
= 25 u - 10 u
= 15 u

Amount that Bryan spends
= 20 u - 10 u
= 10 u

Amount that Charlie spends
= 14 u - 10 u
= 4 u

Amount that they spend
= 15 u + 10 u + 4 u
= 29 u
= 29 x 10
= $290

Answer(s): $290