Bryan, Charlie and Adam have $980.
After Bryan spends ²₃ of his money,
Charlie spends ⁵₇ of his money and
Adam spends ²₅ of his money,
they have equal amount of money left.
Find the total amount that the 3 children spend.

	Bryan	Charlie	Adam
Before	3 x 6 = 18 u	7 x 3 = 21 u	5 x 2 = 10 u
Change	- 2 x 6 = - 12 u	- 5 x 3 = - 15 u	- 2 x 2 = - 4 u
After	1 x 6 =  6 u	2 x 3 = 6 u	3 x 2 = 6 u

The lowest common multiple of 1, 2 and 3 is 6.

Fraction of the amount left after Bryan spends his money
= 1 - ²₃
= ¹₃

Fraction of the amount left after Charlie spends his money
= 1 - ⁵₇
= ²₇

Fraction of the amount left after Adam spends his money
= 1 - ²₅
= ³₅

Make the numerators the same.
1 x 63 x 6 of Bryan's amount = 2 x 37 x 3 of Charlie's amount = 3 x 25 x 2 of Adam's amount
618 of Bryan's amount = 621 of Charlie's amount = 610 of Adam's amount

Total amount that they have at first
= 18 u + 21 u + 10 u
= 49 u

49 u = 980

1 u = 980 ÷ 49 = 20

Amount that Bryan spends
= 18 u - 6 u
= 12 u

Amount that Charlie spends
= 21 u - 6 u
= 15 u

Amount that Adam spends
= 10 u - 6 u
= 4 u

Amount that they spend
= 12 u + 15 u + 4 u
= 31 u
= 31 x 20
= $620

Answer(s): $620