Bryan, Charlie and Adam have $1602.
After Bryan spends ²₃ of his money,
Charlie spends ¹₄ of his money and
Adam spends ³₈ of his money,
they have equal amount of money left.
Find the total amount that the 3 children spend.

	Bryan	Charlie	Adam
Before	3 x 15 = 45 u	4 x 5 = 20 u	8 x 3 = 24 u
Change	- 2 x 15 = - 30 u	- 1 x 5 = - 5 u	- 3 x 3 = - 9 u
After	1 x 15 =  15 u	3 x 5 = 15 u	5 x 3 = 15 u

The lowest common multiple of 1, 3 and 5 is 15.

Fraction of the amount left after Bryan spends his money
= 1 - ²₃
= ¹₃

Fraction of the amount left after Charlie spends his money
= 1 - ¹₄
= ³₄

Fraction of the amount left after Adam spends his money
= 1 - ³₈
= ⁵₈

Make the numerators the same.
1 x 153 x 15 of Bryan's amount = 3 x 54 x 5 of Charlie's amount = 5 x 38 x 3 of Adam's amount
1545 of Bryan's amount = 1520 of Charlie's amount = 1524 of Adam's amount

Total amount that they have at first
= 45 u + 20 u + 24 u
= 89 u

89 u = 1602

1 u = 1602 ÷ 89 = 18

Amount that Bryan spends
= 45 u - 15 u
= 30 u

Amount that Charlie spends
= 20 u - 15 u
= 5 u

Amount that Adam spends
= 24 u - 15 u
= 9 u

Amount that they spend
= 30 u + 5 u + 9 u
= 44 u
= 44 x 18
= $792

Answer(s): $792