Adam, Bryan and Charlie have $1455.
After Adam spends ⁵₇ of his money,
Bryan spends ⁴₅ of his money and
Charlie spends ¹₆ of his money,
they have equal amount of money left.
Find the total amount that the 3 children spend.

	Adam	Bryan	Charlie
Before	7 x 5 = 35 u	5 x 10 = 50 u	6 x 2 = 12 u
Change	- 5 x 5 = - 25 u	- 4 x 10 = - 40 u	- 1 x 2 = - 2 u
After	2 x 5 =  10 u	1 x 10 = 10 u	5 x 2 = 10 u

The lowest common multiple of 2, 1 and 5 is 10.

Fraction of the amount left after Adam spends his money
= 1 - ⁵₇
= ²₇

Fraction of the amount left after Bryan spends his money
= 1 - ⁴₅
= ¹₅

Fraction of the amount left after Charlie spends his money
= 1 - ¹₆
= ⁵₆

Make the numerators the same.
2 x 57 x 5 of Adam's amount = 1 x 105 x 10 of Bryan's amount = 5 x 26 x 2 of Charlie's amount
1035 of Adam's amount = 1050 of Bryan's amount = 1012 of Charlie's amount

Total amount that they have at first
= 35 u + 50 u + 12 u
= 97 u

97 u = 1455

1 u = 1455 ÷ 97 = 15

Amount that Adam spends
= 35 u - 10 u
= 25 u

Amount that Bryan spends
= 50 u - 10 u
= 40 u

Amount that Charlie spends
= 12 u - 10 u
= 2 u

Amount that they spend
= 25 u + 40 u + 2 u
= 67 u
= 67 x 15
= $1005

Answer(s): $1005