Bryan, Charlie and Adam have $1104.
After Bryan spends
35 of his money,
Charlie spends
27 of his money and
Adam spends
23 of his money,
they have equal amount of money left.
Find the total amount that the 3 children spend.
|
Bryan |
Charlie |
Adam |
Before |
5 x 5 = 25 u |
7 x 2 = 14 u |
3 x 10 = 30 u |
Change |
- 3 x 5 = - 15 u |
- 2 x 2 = - 4 u |
- 2 x 10 = - 20 u |
After |
2 x 5 = 10 u |
5 x 2 = 10 u |
1 x 10 = 10 u |
The lowest common multiple of 2, 5 and 1 is 10.
Fraction of the amount left after Bryan spends his money
= 1 -
35 =
25 Fraction of the amount left after Charlie spends his money
= 1 -
27 =
57 Fraction of the amount left after Adam spends his money
= 1 -
23 =
13 Make the numerators the same.
2 x 55 x 5 of Bryan's amount =
5 x 27 x 2 of Charlie's amount =
1 x 103 x 10 of Adam's amount
1025 of Bryan's amount =
1014 of Charlie's amount =
1030 of Adam's amount
Total amount that they have at first
= 25 u + 14 u + 30 u
= 69 u
69 u = 1104
1 u = 1104 ÷ 69 = 16
Amount that Bryan spends
= 25 u - 10 u
= 15 u
Amount that Charlie spends
= 14 u - 10 u
= 4 u
Amount that Adam spends
= 30 u - 10 u
= 20 u
Amount that they spend
= 15 u + 4 u + 20 u
= 39 u
= 39 x 16
= $624
Answer(s): $624