Charlie, Adam and Bryan have $1105.
After Charlie spends
23 of his money,
Adam spends
17 of his money and
Bryan spends
15 of his money,
they have equal amount of money left.
Find the total amount that the 3 children spend.
| |
Charlie |
Adam |
Bryan |
| Before |
3 x 12 =
36 u |
7 x 2 =
14 u |
5 x 3 =
15 u |
| Change |
- 2 x 12 =
- 24 u |
- 1 x 2 =
- 2 u |
- 1 x 3 =
- 3 u |
| After |
1 x 12 =
12 u |
6 x 2 =
12 u |
4 x 3 =
12 u |
The lowest common multiple of 1, 6 and 4 is 12.
Fraction of the amount left after Charlie spends his money
= 1 -
23 =
13 Fraction of the amount left after Adam spends his money
= 1 -
17 =
67 Fraction of the amount left after Bryan spends his money
= 1 -
15 =
45 Make the numerators the same.
1 x 123 x 12 of Charlie's amount =
6 x 27 x 2 of Adam's amount =
4 x 35 x 3 of Bryan's amount
1236 of Charlie's amount =
1214 of Adam's amount =
1215 of Bryan's amount
Total amount that they have at first
= 36 u + 14 u + 15 u
= 65 u
65 u = 1105
1 u = 1105 ÷ 65 = 17
Amount that Charlie spends
= 36 u - 12 u
= 24 u
Amount that Adam spends
= 14 u - 12 u
= 2 u
Amount that Bryan spends
= 15 u - 12 u
= 3 u
Amount that they spend
= 24 u + 2 u + 3 u
= 29 u
= 29 x 17
= $493
Answer(s): $493
