Adam, Charlie and Bryan have $605.
After Adam spends
37 of his money,
Charlie spends
13 of his money and
Bryan spends
14 of his money,
they have equal amount of money left.
Find the total amount that the 3 children spend.
| |
Adam |
Charlie |
Bryan |
| Before |
7 x 3 =
21 u |
3 x 6 =
18 u |
4 x 4 =
16 u |
| Change |
- 3 x 3 =
- 9 u |
- 1 x 6 =
- 6 u |
- 1 x 4 =
- 4 u |
| After |
4 x 3 =
12 u |
2 x 6 =
12 u |
3 x 4 =
12 u |
The lowest common multiple of 4, 2 and 3 is 12.
Fraction of the amount left after Adam spends his money
= 1 -
37 =
47 Fraction of the amount left after Charlie spends his money
= 1 -
13 =
23 Fraction of the amount left after Bryan spends his money
= 1 -
14 =
34 Make the numerators the same.
4 x 37 x 3 of Adam's amount =
2 x 63 x 6 of Charlie's amount =
3 x 44 x 4 of Bryan's amount
1221 of Adam's amount =
1218 of Charlie's amount =
1216 of Bryan's amount
Total amount that they have at first
= 21 u + 18 u + 16 u
= 55 u
55 u = 605
1 u = 605 ÷ 55 = 11
Amount that Adam spends
= 21 u - 12 u
= 9 u
Amount that Charlie spends
= 18 u - 12 u
= 6 u
Amount that Bryan spends
= 16 u - 12 u
= 4 u
Amount that they spend
= 9 u + 6 u + 4 u
= 19 u
= 19 x 11
= $209
Answer(s): $209
