Adam, Bryan and Charlie have $1513.
After Adam spends ²₅ of his money,
Bryan spends ³₄ of his money and
Charlie spends ³₇ of his money,
they have equal amount of money left.
Find the total amount that the 3 children spend.

	Adam	Bryan	Charlie
Before	5 x 4 = 20 u	4 x 12 = 48 u	7 x 3 = 21 u
Change	- 2 x 4 = - 8 u	- 3 x 12 = - 36 u	- 3 x 3 = - 9 u
After	3 x 4 =  12 u	1 x 12 = 12 u	4 x 3 = 12 u

The lowest common multiple of 3, 1 and 4 is 12.

Fraction of the amount left after Adam spends his money
= 1 - ²₅
= ³₅

Fraction of the amount left after Bryan spends his money
= 1 - ³₄
= ¹₄

Fraction of the amount left after Charlie spends his money
= 1 - ³₇
= ⁴₇

Make the numerators the same.
3 x 45 x 4 of Adam's amount = 1 x 124 x 12 of Bryan's amount = 4 x 37 x 3 of Charlie's amount
1220 of Adam's amount = 1248 of Bryan's amount = 1221 of Charlie's amount

Total amount that they have at first
= 20 u + 48 u + 21 u
= 89 u

89 u = 1513

1 u = 1513 ÷ 89 = 17

Amount that Adam spends
= 20 u - 12 u
= 8 u

Amount that Bryan spends
= 48 u - 12 u
= 36 u

Amount that Charlie spends
= 21 u - 12 u
= 9 u

Amount that they spend
= 8 u + 36 u + 9 u
= 53 u
= 53 x 17
= $901

Answer(s): $901