Charlie, Bryan and Adam have $1320.
After Charlie spends
23 of his money,
Bryan spends
16 of his money and
Adam spends
25 of his money,
they have equal amount of money left.
Find the total amount that the 3 children spend.
|
Charlie |
Bryan |
Adam |
Before |
3 x 15 = 45 u |
6 x 3 = 18 u |
5 x 5 = 25 u |
Change |
- 2 x 15 = - 30 u |
- 1 x 3 = - 3 u |
- 2 x 5 = - 10 u |
After |
1 x 15 = 15 u |
5 x 3 = 15 u |
3 x 5 = 15 u |
The lowest common multiple of 1, 5 and 3 is 15.
Fraction of the amount left after Charlie spends his money
= 1 -
23 =
13 Fraction of the amount left after Bryan spends his money
= 1 -
16 =
56 Fraction of the amount left after Adam spends his money
= 1 -
25 =
35 Make the numerators the same.
1 x 153 x 15 of Charlie's amount =
5 x 36 x 3 of Bryan's amount =
3 x 55 x 5 of Adam's amount
1545 of Charlie's amount =
1518 of Bryan's amount =
1525 of Adam's amount
Total amount that they have at first
= 45 u + 18 u + 25 u
= 88 u
88 u = 1320
1 u = 1320 ÷ 88 = 15
Amount that Charlie spends
= 45 u - 15 u
= 30 u
Amount that Bryan spends
= 18 u - 15 u
= 3 u
Amount that Adam spends
= 25 u - 15 u
= 10 u
Amount that they spend
= 30 u + 3 u + 10 u
= 43 u
= 43 x 15
= $645
Answer(s): $645