Adam, Charlie and Bryan have $1072.
After Adam spends ³₅ of his money,
Charlie spends ³₇ of his money and
Bryan spends ¹₄ of his money,
they have equal amount of money left.
Find the total amount that the 3 children spend.

	Adam	Charlie	Bryan
Before	5 x 6 = 30 u	7 x 3 = 21 u	4 x 4 = 16 u
Change	- 3 x 6 = - 18 u	- 3 x 3 = - 9 u	- 1 x 4 = - 4 u
After	2 x 6 =  12 u	4 x 3 = 12 u	3 x 4 = 12 u

The lowest common multiple of 2, 4 and 3 is 12.

Fraction of the amount left after Adam spends his money
= 1 - ³₅
= ²₅

Fraction of the amount left after Charlie spends his money
= 1 - ³₇
= ⁴₇

Fraction of the amount left after Bryan spends his money
= 1 - ¹₄
= ³₄

Make the numerators the same.
2 x 65 x 6 of Adam's amount = 4 x 37 x 3 of Charlie's amount = 3 x 44 x 4 of Bryan's amount
1230 of Adam's amount = 1221 of Charlie's amount = 1216 of Bryan's amount

Total amount that they have at first
= 30 u + 21 u + 16 u
= 67 u

67 u = 1072

1 u = 1072 ÷ 67 = 16

Amount that Adam spends
= 30 u - 12 u
= 18 u

Amount that Charlie spends
= 21 u - 12 u
= 9 u

Amount that Bryan spends
= 16 u - 12 u
= 4 u

Amount that they spend
= 18 u + 9 u + 4 u
= 31 u
= 31 x 16
= $496

Answer(s): $496