Charlie, Adam and Bryan have $860.
After Charlie spends ³₅ of his money,
Adam spends ¹₁₀ of his money and
Bryan spends ¹₇ of his money,
they have equal amount of money left.
Find the total amount that the 3 children spend.

	Charlie	Adam	Bryan
Before	5 x 9 = 45 u	10 x 2 = 20 u	7 x 3 = 21 u
Change	- 3 x 9 = - 27 u	- 1 x 2 = - 2 u	- 1 x 3 = - 3 u
After	2 x 9 =  18 u	9 x 2 = 18 u	6 x 3 = 18 u

The lowest common multiple of 2, 9 and 6 is 18.

Fraction of the amount left after Charlie spends his money
= 1 - ³₅
= ²₅

Fraction of the amount left after Adam spends his money
= 1 - ¹₁₀
= ⁹₁₀

Fraction of the amount left after Bryan spends his money
= 1 - ¹₇
= ⁶₇

Make the numerators the same.
2 x 95 x 9 of Charlie's amount = 9 x 210 x 2 of Adam's amount = 6 x 37 x 3 of Bryan's amount
1845 of Charlie's amount = 1820 of Adam's amount = 1821 of Bryan's amount

Total amount that they have at first
= 45 u + 20 u + 21 u
= 86 u

86 u = 860

1 u = 860 ÷ 86 = 10

Amount that Charlie spends
= 45 u - 18 u
= 27 u

Amount that Adam spends
= 20 u - 18 u
= 2 u

Amount that Bryan spends
= 21 u - 18 u
= 3 u

Amount that they spend
= 27 u + 2 u + 3 u
= 32 u
= 32 x 10
= $320

Answer(s): $320