Charlie, Bryan and Adam have $1691.
After Charlie spends ³₄ of his money,
Bryan spends ³₇ of his money and
Adam spends ²₅ of his money,
they have equal amount of money left.
Find the total amount that the 3 children spend.

	Charlie	Bryan	Adam
Before	4 x 12 = 48 u	7 x 3 = 21 u	5 x 4 = 20 u
Change	- 3 x 12 = - 36 u	- 3 x 3 = - 9 u	- 2 x 4 = - 8 u
After	1 x 12 =  12 u	4 x 3 = 12 u	3 x 4 = 12 u

The lowest common multiple of 1, 4 and 3 is 12.

Fraction of the amount left after Charlie spends his money
= 1 - ³₄
= ¹₄

Fraction of the amount left after Bryan spends his money
= 1 - ³₇
= ⁴₇

Fraction of the amount left after Adam spends his money
= 1 - ²₅
= ³₅

Make the numerators the same.
1 x 124 x 12 of Charlie's amount = 4 x 37 x 3 of Bryan's amount = 3 x 45 x 4 of Adam's amount
1248 of Charlie's amount = 1221 of Bryan's amount = 1220 of Adam's amount

Total amount that they have at first
= 48 u + 21 u + 20 u
= 89 u

89 u = 1691

1 u = 1691 ÷ 89 = 19

Amount that Charlie spends
= 48 u - 12 u
= 36 u

Amount that Bryan spends
= 21 u - 12 u
= 9 u

Amount that Adam spends
= 20 u - 12 u
= 8 u

Amount that they spend
= 36 u + 9 u + 8 u
= 53 u
= 53 x 19
= $1007

Answer(s): $1007