Bryan, Charlie and Adam have $1022.
After Bryan spends ²₅ of his money,
Charlie spends ¹₆ of his money and
Adam spends ¹₂ of his money,
they have equal amount of money left.
Find the total amount that the 3 children spend.

	Bryan	Charlie	Adam
Before	5 x 5 = 25 u	6 x 3 = 18 u	2 x 15 = 30 u
Change	- 2 x 5 = - 10 u	- 1 x 3 = - 3 u	- 1 x 15 = - 15 u
After	3 x 5 =  15 u	5 x 3 = 15 u	1 x 15 = 15 u

The lowest common multiple of 3, 5 and 1 is 15.

Fraction of the amount left after Bryan spends his money
= 1 - ²₅
= ³₅

Fraction of the amount left after Charlie spends his money
= 1 - ¹₆
= ⁵₆

Fraction of the amount left after Adam spends his money
= 1 - ¹₂
= ¹₂

Make the numerators the same.
3 x 55 x 5 of Bryan's amount = 5 x 36 x 3 of Charlie's amount = 1 x 152 x 15 of Adam's amount
1525 of Bryan's amount = 1518 of Charlie's amount = 1530 of Adam's amount

Total amount that they have at first
= 25 u + 18 u + 30 u
= 73 u

73 u = 1022

1 u = 1022 ÷ 73 = 14

Amount that Bryan spends
= 25 u - 15 u
= 10 u

Amount that Charlie spends
= 18 u - 15 u
= 3 u

Amount that Adam spends
= 30 u - 15 u
= 15 u

Amount that they spend
= 10 u + 3 u + 15 u
= 28 u
= 28 x 14
= $392

Answer(s): $392