Adam, Charlie and Bryan have $1463.
After Adam spends ²₃ of his money,
Charlie spends ⁵₇ of his money and
Bryan spends ¹₆ of his money,
they have equal amount of money left.
Find the total amount that the 3 children spend.

	Adam	Charlie	Bryan
Before	3 x 10 = 30 u	7 x 5 = 35 u	6 x 2 = 12 u
Change	- 2 x 10 = - 20 u	- 5 x 5 = - 25 u	- 1 x 2 = - 2 u
After	1 x 10 =  10 u	2 x 5 = 10 u	5 x 2 = 10 u

The lowest common multiple of 1, 2 and 5 is 10.

Fraction of the amount left after Adam spends his money
= 1 - ²₃
= ¹₃

Fraction of the amount left after Charlie spends his money
= 1 - ⁵₇
= ²₇

Fraction of the amount left after Bryan spends his money
= 1 - ¹₆
= ⁵₆

Make the numerators the same.
1 x 103 x 10 of Adam's amount = 2 x 57 x 5 of Charlie's amount = 5 x 26 x 2 of Bryan's amount
1030 of Adam's amount = 1035 of Charlie's amount = 1012 of Bryan's amount

Total amount that they have at first
= 30 u + 35 u + 12 u
= 77 u

77 u = 1463

1 u = 1463 ÷ 77 = 19

Amount that Adam spends
= 30 u - 10 u
= 20 u

Amount that Charlie spends
= 35 u - 10 u
= 25 u

Amount that Bryan spends
= 12 u - 10 u
= 2 u

Amount that they spend
= 20 u + 25 u + 2 u
= 47 u
= 47 x 19
= $893

Answer(s): $893