Bryan, Charlie and Adam have $994.
After Bryan spends
58 of his money,
Charlie spends
15 of his money and
Adam spends
12 of his money,
they have equal amount of money left.
Find the total amount that the 3 children spend.
|
Bryan |
Charlie |
Adam |
Before |
8 x 4 = 32 u |
5 x 3 = 15 u |
2 x 12 = 24 u |
Change |
- 5 x 4 = - 20 u |
- 1 x 3 = - 3 u |
- 1 x 12 = - 12 u |
After |
3 x 4 = 12 u |
4 x 3 = 12 u |
1 x 12 = 12 u |
The lowest common multiple of 3, 4 and 1 is 12.
Fraction of the amount left after Bryan spends his money
= 1 -
58 =
38 Fraction of the amount left after Charlie spends his money
= 1 -
15 =
45 Fraction of the amount left after Adam spends his money
= 1 -
12 =
12 Make the numerators the same.
3 x 48 x 4 of Bryan's amount =
4 x 35 x 3 of Charlie's amount =
1 x 122 x 12 of Adam's amount
1232 of Bryan's amount =
1215 of Charlie's amount =
1224 of Adam's amount
Total amount that they have at first
= 32 u + 15 u + 24 u
= 71 u
71 u = 994
1 u = 994 ÷ 71 = 14
Amount that Bryan spends
= 32 u - 12 u
= 20 u
Amount that Charlie spends
= 15 u - 12 u
= 3 u
Amount that Adam spends
= 24 u - 12 u
= 12 u
Amount that they spend
= 20 u + 3 u + 12 u
= 35 u
= 35 x 14
= $490
Answer(s): $490