Bryan, Adam and Charlie have $1960.
After Bryan spends
23 of his money,
Adam spends
16 of his money and
Charlie spends
47 of his money,
they have equal amount of money left.
Find the total amount that the 3 children spend.
|
Bryan |
Adam |
Charlie |
Before |
3 x 15 = 45 u |
6 x 3 = 18 u |
7 x 5 = 35 u |
Change |
- 2 x 15 = - 30 u |
- 1 x 3 = - 3 u |
- 4 x 5 = - 20 u |
After |
1 x 15 = 15 u |
5 x 3 = 15 u |
3 x 5 = 15 u |
The lowest common multiple of 1, 5 and 3 is 15.
Fraction of the amount left after Bryan spends his money
= 1 -
23 =
13 Fraction of the amount left after Adam spends his money
= 1 -
16 =
56 Fraction of the amount left after Charlie spends his money
= 1 -
47 =
37 Make the numerators the same.
1 x 153 x 15 of Bryan's amount =
5 x 36 x 3 of Adam's amount =
3 x 57 x 5 of Charlie's amount
1545 of Bryan's amount =
1518 of Adam's amount =
1535 of Charlie's amount
Total amount that they have at first
= 45 u + 18 u + 35 u
= 98 u
98 u = 1960
1 u = 1960 ÷ 98 = 20
Amount that Bryan spends
= 45 u - 15 u
= 30 u
Amount that Adam spends
= 18 u - 15 u
= 3 u
Amount that Charlie spends
= 35 u - 15 u
= 20 u
Amount that they spend
= 30 u + 3 u + 20 u
= 53 u
= 53 x 20
= $1060
Answer(s): $1060