Adam, Bryan and Charlie have $710.
After Adam spends
35 of his money,
Bryan spends
38 of his money and
Charlie spends
23 of his money,
they have equal amount of money left.
Find the total amount that the 3 children spend.
|
Adam |
Bryan |
Charlie |
Before |
5 x 5 = 25 u |
8 x 2 = 16 u |
3 x 10 = 30 u |
Change |
- 3 x 5 = - 15 u |
- 3 x 2 = - 6 u |
- 2 x 10 = - 20 u |
After |
2 x 5 = 10 u |
5 x 2 = 10 u |
1 x 10 = 10 u |
The lowest common multiple of 2, 5 and 1 is 10.
Fraction of the amount left after Adam spends his money
= 1 -
35 =
25 Fraction of the amount left after Bryan spends his money
= 1 -
38 =
58 Fraction of the amount left after Charlie spends his money
= 1 -
23 =
13 Make the numerators the same.
2 x 55 x 5 of Adam's amount =
5 x 28 x 2 of Bryan's amount =
1 x 103 x 10 of Charlie's amount
1025 of Adam's amount =
1016 of Bryan's amount =
1030 of Charlie's amount
Total amount that they have at first
= 25 u + 16 u + 30 u
= 71 u
71 u = 710
1 u = 710 ÷ 71 = 10
Amount that Adam spends
= 25 u - 10 u
= 15 u
Amount that Bryan spends
= 16 u - 10 u
= 6 u
Amount that Charlie spends
= 30 u - 10 u
= 20 u
Amount that they spend
= 15 u + 6 u + 20 u
= 41 u
= 41 x 10
= $410
Answer(s): $410