Charlie, Adam and Bryan have $1100.
After Charlie spends ²₅ of his money,
Adam spends ⁵₇ of his money and
Bryan spends ³₄ of his money,
they have equal amount of money left.
Find the total amount that the 3 children spend.

	Charlie	Adam	Bryan
Before	5 x 2 = 10 u	7 x 3 = 21 u	4 x 6 = 24 u
Change	- 2 x 2 = - 4 u	- 5 x 3 = - 15 u	- 3 x 6 = - 18 u
After	3 x 2 =  6 u	2 x 3 = 6 u	1 x 6 = 6 u

The lowest common multiple of 3, 2 and 1 is 6.

Fraction of the amount left after Charlie spends his money
= 1 - ²₅
= ³₅

Fraction of the amount left after Adam spends his money
= 1 - ⁵₇
= ²₇

Fraction of the amount left after Bryan spends his money
= 1 - ³₄
= ¹₄

Make the numerators the same.
3 x 25 x 2 of Charlie's amount = 2 x 37 x 3 of Adam's amount = 1 x 64 x 6 of Bryan's amount
610 of Charlie's amount = 621 of Adam's amount = 624 of Bryan's amount

Total amount that they have at first
= 10 u + 21 u + 24 u
= 55 u

55 u = 1100

1 u = 1100 ÷ 55 = 20

Amount that Charlie spends
= 10 u - 6 u
= 4 u

Amount that Adam spends
= 21 u - 6 u
= 15 u

Amount that Bryan spends
= 24 u - 6 u
= 18 u

Amount that they spend
= 4 u + 15 u + 18 u
= 37 u
= 37 x 20
= $740

Answer(s): $740