Bryan, Adam and Charlie have $1261.
After Bryan spends ⁵₇ of his money,
Adam spends ¹₆ of his money and
Charlie spends ⁴₅ of his money,
they have equal amount of money left.
Find the total amount that the 3 children spend.

	Bryan	Adam	Charlie
Before	7 x 5 = 35 u	6 x 2 = 12 u	5 x 10 = 50 u
Change	- 5 x 5 = - 25 u	- 1 x 2 = - 2 u	- 4 x 10 = - 40 u
After	2 x 5 =  10 u	5 x 2 = 10 u	1 x 10 = 10 u

The lowest common multiple of 2, 5 and 1 is 10.

Fraction of the amount left after Bryan spends his money
= 1 - ⁵₇
= ²₇

Fraction of the amount left after Adam spends his money
= 1 - ¹₆
= ⁵₆

Fraction of the amount left after Charlie spends his money
= 1 - ⁴₅
= ¹₅

Make the numerators the same.
2 x 57 x 5 of Bryan's amount = 5 x 26 x 2 of Adam's amount = 1 x 105 x 10 of Charlie's amount
1035 of Bryan's amount = 1012 of Adam's amount = 1050 of Charlie's amount

Total amount that they have at first
= 35 u + 12 u + 50 u
= 97 u

97 u = 1261

1 u = 1261 ÷ 97 = 13

Amount that Bryan spends
= 35 u - 10 u
= 25 u

Amount that Adam spends
= 12 u - 10 u
= 2 u

Amount that Charlie spends
= 50 u - 10 u
= 40 u

Amount that they spend
= 25 u + 2 u + 40 u
= 67 u
= 67 x 13
= $871

Answer(s): $871