Charlie, Adam and Bryan have $490.
After Charlie spends
58 of his money,
Adam spends
23 of his money and
Bryan spends
35 of his money,
they have equal amount of money left.
Find the total amount that the 3 children spend.
|
Charlie |
Adam |
Bryan |
Before |
8 x 2 = 16 u |
3 x 6 = 18 u |
5 x 3 = 15 u |
Change |
- 5 x 2 = - 10 u |
- 2 x 6 = - 12 u |
- 3 x 3 = - 9 u |
After |
3 x 2 = 6 u |
1 x 6 = 6 u |
2 x 3 = 6 u |
The lowest common multiple of 3, 1 and 2 is 6.
Fraction of the amount left after Charlie spends his money
= 1 -
58 =
38 Fraction of the amount left after Adam spends his money
= 1 -
23 =
13 Fraction of the amount left after Bryan spends his money
= 1 -
35 =
25 Make the numerators the same.
3 x 28 x 2 of Charlie's amount =
1 x 63 x 6 of Adam's amount =
2 x 35 x 3 of Bryan's amount
616 of Charlie's amount =
618 of Adam's amount =
615 of Bryan's amount
Total amount that they have at first
= 16 u + 18 u + 15 u
= 49 u
49 u = 490
1 u = 490 ÷ 49 = 10
Amount that Charlie spends
= 16 u - 6 u
= 10 u
Amount that Adam spends
= 18 u - 6 u
= 12 u
Amount that Bryan spends
= 15 u - 6 u
= 9 u
Amount that they spend
= 10 u + 12 u + 9 u
= 31 u
= 31 x 10
= $310
Answer(s): $310