Bryan, Charlie and Adam have $793.
After Bryan spends ³₈ of his money,
Charlie spends ³₅ of his money and
Adam spends ¹₂ of his money,
they have equal amount of money left.
Find the total amount that the 3 children spend.

	Bryan	Charlie	Adam
Before	8 x 2 = 16 u	5 x 5 = 25 u	2 x 10 = 20 u
Change	- 3 x 2 = - 6 u	- 3 x 5 = - 15 u	- 1 x 10 = - 10 u
After	5 x 2 =  10 u	2 x 5 = 10 u	1 x 10 = 10 u

The lowest common multiple of 5, 2 and 1 is 10.

Fraction of the amount left after Bryan spends his money
= 1 - ³₈
= ⁵₈

Fraction of the amount left after Charlie spends his money
= 1 - ³₅
= ²₅

Fraction of the amount left after Adam spends his money
= 1 - ¹₂
= ¹₂

Make the numerators the same.
5 x 28 x 2 of Bryan's amount = 2 x 55 x 5 of Charlie's amount = 1 x 102 x 10 of Adam's amount
1016 of Bryan's amount = 1025 of Charlie's amount = 1020 of Adam's amount

Total amount that they have at first
= 16 u + 25 u + 20 u
= 61 u

61 u = 793

1 u = 793 ÷ 61 = 13

Amount that Bryan spends
= 16 u - 10 u
= 6 u

Amount that Charlie spends
= 25 u - 10 u
= 15 u

Amount that Adam spends
= 20 u - 10 u
= 10 u

Amount that they spend
= 6 u + 15 u + 10 u
= 31 u
= 31 x 13
= $403

Answer(s): $403