Adam, Charlie and Bryan have $1820.
After Adam spends
47 of his money,
Charlie spends
15 of his money and
Bryan spends
34 of his money,
they have equal amount of money left.
Find the total amount that the 3 children spend.
|
Adam |
Charlie |
Bryan |
Before |
7 x 4 = 28 u |
5 x 3 = 15 u |
4 x 12 = 48 u |
Change |
- 4 x 4 = - 16 u |
- 1 x 3 = - 3 u |
- 3 x 12 = - 36 u |
After |
3 x 4 = 12 u |
4 x 3 = 12 u |
1 x 12 = 12 u |
The lowest common multiple of 3, 4 and 1 is 12.
Fraction of the amount left after Adam spends his money
= 1 -
47 =
37 Fraction of the amount left after Charlie spends his money
= 1 -
15 =
45 Fraction of the amount left after Bryan spends his money
= 1 -
34 =
14 Make the numerators the same.
3 x 47 x 4 of Adam's amount =
4 x 35 x 3 of Charlie's amount =
1 x 124 x 12 of Bryan's amount
1228 of Adam's amount =
1215 of Charlie's amount =
1248 of Bryan's amount
Total amount that they have at first
= 28 u + 15 u + 48 u
= 91 u
91 u = 1820
1 u = 1820 ÷ 91 = 20
Amount that Adam spends
= 28 u - 12 u
= 16 u
Amount that Charlie spends
= 15 u - 12 u
= 3 u
Amount that Bryan spends
= 48 u - 12 u
= 36 u
Amount that they spend
= 16 u + 3 u + 36 u
= 55 u
= 55 x 20
= $1100
Answer(s): $1100