Adam has 410 stickers.
After
13 of the red stickers and
30 blue stickers are given away,
there is an equal number of red and blue stickers left.
- How many red stickers are there in the end?
- How many more red stickers than blue stickers are there at first?
- How many red stickers are given away?
|
Red stickers |
Blue stickers |
Total |
Before |
3 u |
2 u + 30 |
410 |
Change |
- 1 u |
- 30 |
|
After |
2 u |
2 u |
|
(a)
Fraction of the red stickers left
= 1 -
13 =
23 Total number of stickers at first
= 3 u + 2 u + 30
= 5 u + 30
5 u + 30 = 410
5 u = 410 - 30
5 u = 380
1 u = 380 ÷ 5 = 76
Number of red stickers in the end
= 2 u
= 2 x 76
= 152
(b)
Number of more red stickers than blue stickers at first
= 3 u - (2 u + 30)
= 3 u - 2 u - 30
= 1 u - 30
= 1 x 76 - 30
= 76 - 30
= 46
(c)
Number of red stickers given away
= 1 u
= 76
Answer(s): (a) 152; (b) 46; (c) 76