Adam has 410 stickers.
After
18 of the green stickers and
20 red stickers are given away,
there is an equal number of green and red stickers left.
- How many green stickers are there in the end?
- How many more green stickers than red stickers are there at first?
- How many green stickers are given away?
|
Green stickers |
Red stickers |
Total |
Before |
8 u |
7 u + 20 |
410 |
Change |
- 1 u |
- 20 |
|
After |
7 u |
7 u |
|
(a)
Fraction of the green stickers left
= 1 -
18 =
78 Total number of stickers at first
= 8 u + 7 u + 20
= 15 u + 20
15 u + 20 = 410
15 u = 410 - 20
15 u = 390
1 u = 390 ÷ 15 = 26
Number of green stickers in the end
= 7 u
= 7 x 26
= 182
(b)
Number of more green stickers than red stickers at first
= 8 u - (7 u + 20)
= 8 u - 7 u - 20
= 1 u - 20
= 1 x 26 - 20
= 26 - 20
= 6
(c)
Number of green stickers given away
= 1 u
= 26
Answer(s): (a) 182; (b) 6; (c) 26